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		<title>Advanced Quantum Field Theory II &#8211; Week 15</title>
		<link>http://indexguy.wordpress.com/2009/05/04/advanced-quantum-field-theory-ii-week-15/</link>
		<comments>http://indexguy.wordpress.com/2009/05/04/advanced-quantum-field-theory-ii-week-15/#comments</comments>
		<pubDate>Tue, 05 May 2009 02:44:57 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Quantum Field Theory]]></category>
		<category><![CDATA[Supersymmetry]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=272</guid>
		<description><![CDATA[The last week of the semester was dedicated to Feynman rules in superspace. Before we go into that, it is good to review and set our conventions in superspace.
A remark: as in any quantum field theory analysis, here we will see the need for regularization. Now we need to to preserve the supersymmetry of the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=272&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>The last week of the semester was dedicated to Feynman rules in superspace. Before we go into that, it is good to review and set our conventions in superspace.</p>
<p>A remark: as in any quantum field theory analysis, here we will see the need for regularization. Now we need to to preserve the supersymmetry of the theory and the task of finding a regulator that obeys this criteria is non-trivial. Nevertheless, there exist such regularization schemes, namely dimensional reduction.</p>
<p>In any case, as action we will take the Wess-Zumino model coupled to super Yang-Mills. Of course this theory only has simple supersymmetry, but actually this is one of the only cases where superspace methods are useful. I do not want to rule out superspace methods for extended supersymmetry since one never knows what one might end up doing for his/her Ph.D. thesis. <img src='http://s.wordpress.com/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' />  The action has the form:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=S+%3D+%5Cdisplaystyle%5Cint+d%5E%7B4%7D+x+d%5E%7B4%7D+%5Ctheta+%5Cbar%7B%5Cphi%7De%5E%7BV%7D%5Cphi+%2B+%5Cint+d%5E%7B4%7Dx+d%5E%7B2%7D%5Ctheta+W%5Cleft%28%5Ctheta%5Cright%29+%2B+h.c.+%2B+S_%7BSYM%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='S = \displaystyle\int d^{4} x d^{4} \theta \bar{\phi}e^{V}\phi + \int d^{4}x d^{2}\theta W\left(\theta\right) + h.c. + S_{SYM}' title='S = \displaystyle\int d^{4} x d^{4} \theta \bar{\phi}e^{V}\phi + \int d^{4}x d^{2}\theta W\left(\theta\right) + h.c. + S_{SYM}' class='latex' />.</p>
<p>The prepotential is</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=W%5Cleft%28%5Ctheta%5Cright%29+%3D+%5Cdisplaystyle%5Cfrac%7B1%7D%7B2%7Dm+%5Cphi%5E%7B2%7D+%2B+%5Cfrac%7B1%7D%7B3%21%7D%5Clambda+%5Cphi%5E%7B3%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='W\left(\theta\right) = \displaystyle\frac{1}{2}m \phi^{2} + \frac{1}{3!}\lambda \phi^{3}' title='W\left(\theta\right) = \displaystyle\frac{1}{2}m \phi^{2} + \frac{1}{3!}\lambda \phi^{3}' class='latex' />.</p>
<p>In four-dimensional Minkowski spacetime the Lorentz group <img src='http://l.wordpress.com/latex.php?latex=SO%281%2C3%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='SO(1,3)' title='SO(1,3)' class='latex' /> is doubly covered by <img src='http://l.wordpress.com/latex.php?latex=SL%282%2C+%5Cmathbb%7BC%7D%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='SL(2, \mathbb{C})' title='SL(2, \mathbb{C})' class='latex' />. We will label spinors with a Weyl index <img src='http://l.wordpress.com/latex.php?latex=%5Calpha%2C+%5Cdot%7B%5Calpha%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\alpha, \dot{\alpha}' title='\alpha, \dot{\alpha}' class='latex' />. The supercovariant derivatives, (giving objects that are covariant under supersymmetric transformations) are defined as follows:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=D_%7B%5Calpha%7D+%3D+%5Cdisplaystyle+%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+%5Ctheta%5E%7B%5Calpha%7D%7D+-+i+%5Csigma%5E%7Ba%7D+_%7B%5Calpha+%5Cdot%7B%5Cbeta%7D%7D%5Ctheta%5E%7B%5Cdot%7B%5Cbeta%7D%7D%5Cpartial_%7Ba%7D+%5Cqquad+%5Cbar%7BD%7D_%7B%5Cdot%7B%5Calpha%7D%7D+%3D+%5Cdisplaystyle%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+%5Cbar%7B%5Ctheta%7D%5E%7B%5Cdot%7B%5Calpha%7D%7D%7D+-+i+%5Csigma%5E%7Ba%7D+_%7B%5Cbeta+%5Cdot%7B%5Calpha%7D%7D%5Ctheta%5E%7B%5Cbeta%7D%5Cpartial_%7Ba%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='D_{\alpha} = \displaystyle \frac{\partial}{\partial \theta^{\alpha}} - i \sigma^{a} _{\alpha \dot{\beta}}\theta^{\dot{\beta}}\partial_{a} \qquad \bar{D}_{\dot{\alpha}} = \displaystyle\frac{\partial}{\partial \bar{\theta}^{\dot{\alpha}}} - i \sigma^{a} _{\beta \dot{\alpha}}\theta^{\beta}\partial_{a}' title='D_{\alpha} = \displaystyle \frac{\partial}{\partial \theta^{\alpha}} - i \sigma^{a} _{\alpha \dot{\beta}}\theta^{\dot{\beta}}\partial_{a} \qquad \bar{D}_{\dot{\alpha}} = \displaystyle\frac{\partial}{\partial \bar{\theta}^{\dot{\alpha}}} - i \sigma^{a} _{\beta \dot{\alpha}}\theta^{\beta}\partial_{a}' class='latex' /></p>
<p>Now we set the convention for raising and lowering Weyl indices (which actually we do not follow in the definition of the supercovariant derivatives): Weyl indices are raised with the two-dimensional antisymmetric symbol in the ¨from north-west to south-east¨ fashion. Namely,</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cpsi%5E%7B%5Calpha%7D+%3D+%5Cepsilon%5E%7B%5Calpha+%5Cbeta%7D+%5Cpsi_%7B%5Cbeta%7D+%5Cqquad+%5Cbar%7B%5Cpsi%7D%5E%7B%5Cdot%7B%5Calpha%7D%7D+%3D+%5Cepsilon%5E%7B%5Cdot%7B%5Calpha%7D+%5Cdot%7B%5Cbeta%7D%7D+%5Cbar%7B%5Cpsi%7D_%7B%5Cdot%7B%5Cbeta%7D%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\psi^{\alpha} = \epsilon^{\alpha \beta} \psi_{\beta} \qquad \bar{\psi}^{\dot{\alpha}} = \epsilon^{\dot{\alpha} \dot{\beta}} \bar{\psi}_{\dot{\beta}}' title='\psi^{\alpha} = \epsilon^{\alpha \beta} \psi_{\beta} \qquad \bar{\psi}^{\dot{\alpha}} = \epsilon^{\dot{\alpha} \dot{\beta}} \bar{\psi}_{\dot{\beta}}' class='latex' /></p>
<p style="text-align:left;">The bars on spinors with dotted indices will be omited in what follows (they are redundant anyway). For example, we have the anticommutators for the supercovariant derivatives:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cleft%5C%7B+D_%7B%5Calpha%7D%2C+D_%7B%5Cdot%7B%5Cbeta%7D%7D+%5Cright%5C%7D+%3D+-2i+%5Csigma%5E%7Ba%7D_%7B%5Calpha+%5Cdot%7B%5Cbeta%7D%7D%5Cpartial_%7Ba%7D+%5Cqquad+%5Cleft%5C%7BD_%7B%5Calpha%7D%2C+D_%7B%5Cbeta%7D%5Cright%5C%7D+%3D+0+%5Cqquad+%5Cleft%5C%7B+D_%7B%5Cdot%7B%5Calpha%7D%7D%2C+D_%7B%5Cdot%7B%5Cbeta%7D%7D%5Cright%5C%7D+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\left\{ D_{\alpha}, D_{\dot{\beta}} \right\} = -2i \sigma^{a}_{\alpha \dot{\beta}}\partial_{a} \qquad \left\{D_{\alpha}, D_{\beta}\right\} = 0 \qquad \left\{ D_{\dot{\alpha}}, D_{\dot{\beta}}\right\} = 0' title='\displaystyle\left\{ D_{\alpha}, D_{\dot{\beta}} \right\} = -2i \sigma^{a}_{\alpha \dot{\beta}}\partial_{a} \qquad \left\{D_{\alpha}, D_{\beta}\right\} = 0 \qquad \left\{ D_{\dot{\alpha}}, D_{\dot{\beta}}\right\} = 0' class='latex' /></p>
<p><!-- p, li { white-space: pre-wrap; } --> <!-- p, li { white-space: pre-wrap; } --> <!-- p, li { white-space: pre-wrap; } --></p>
<p style="text-align:left;">Now we move on to integration. We start with</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B2%7D+%5Ctheta+%5Ctheta%5E%7B2%7D+%3D+%5Cint+%5Cfrac%7B1%7D%7B2%7Dd%5Ctheta%5E%7B1%7Dd%5Ctheta%5E%7B2%7D+%5Ctheta%5E%7B%5Calpha%7D%5Ctheta_%7B%5Calpha%7D+%3D+1&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{2} \theta \theta^{2} = \int \frac{1}{2}d\theta^{1}d\theta^{2} \theta^{\alpha}\theta_{\alpha} = 1' title='\displaystyle \int d^{2} \theta \theta^{2} = \int \frac{1}{2}d\theta^{1}d\theta^{2} \theta^{\alpha}\theta_{\alpha} = 1' class='latex' /></p>
<p style="text-align:left;">Similarly for the dotted coordinates:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B2%7D+%5Cbar%7B%5Ctheta%7D+%5Cbar%7B%5Ctheta%7D%5E%7B2%7D+%3D+%5Cint+%5Cfrac%7B1%7D%7B2%7Dd%5Cbar%7B%5Ctheta%7D%5E%7B2%7Dd%5Cbar%7B%5Ctheta%7D%5E%7B1%7D+%5Ctheta%5E%7B%5Cdot%7B%5Calpha%7D%7D%5Ctheta_%7B%5Cdot%7B%5Calpha%7D%7D+%3D+1&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{2} \bar{\theta} \bar{\theta}^{2} = \int \frac{1}{2}d\bar{\theta}^{2}d\bar{\theta}^{1} \theta^{\dot{\alpha}}\theta_{\dot{\alpha}} = 1' title='\displaystyle \int d^{2} \bar{\theta} \bar{\theta}^{2} = \int \frac{1}{2}d\bar{\theta}^{2}d\bar{\theta}^{1} \theta^{\dot{\alpha}}\theta_{\dot{\alpha}} = 1' class='latex' /></p>
<p style="text-align:left;">This expression follows from the single integration:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5Ctheta%5E%7B%5Calpha%7D+%5Ctheta%5E%7B%5Cbeta%7D+%3D+%5Cdelta%5E%7B%5Calpha+%5Cbeta%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d\theta^{\alpha} \theta^{\beta} = \delta^{\alpha \beta}' title='\displaystyle \int d\theta^{\alpha} \theta^{\beta} = \delta^{\alpha \beta}' class='latex' /></p>
<p style="text-align:left;">The integral of anticommuting variables can be written in terms of the derivative.</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B2%7D+%5Ctheta+%5Cleft%28%5Ccdot%5Cright%29+%3D+-%5Cfrac%7B1%7D%7B4%7D%5Cpartial%5E%7B%5Calpha%7D%5Cpartial_%7B%5Calpha%7D%5Cleft%28%5Ccdot%5Cright%29+%5Cqquad+%5Cint+d%5E%7B2%7D+%5Cbar%7B%5Ctheta%7D+%5Cleft%28%5Ccdot%5Cright%29+%3D+-%5Cfrac%7B1%7D%7B4%7D%5Cpartial%5E%7B%5Cdot%7B%5Calpha%7D%7D%5Cpartial_%7B%5Cdot%7B%5Calpha%7D%7D%5Cleft%28%5Ccdot%5Cright%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{2} \theta \left(\cdot\right) = -\frac{1}{4}\partial^{\alpha}\partial_{\alpha}\left(\cdot\right) \qquad \int d^{2} \bar{\theta} \left(\cdot\right) = -\frac{1}{4}\partial^{\dot{\alpha}}\partial_{\dot{\alpha}}\left(\cdot\right)' title='\displaystyle \int d^{2} \theta \left(\cdot\right) = -\frac{1}{4}\partial^{\alpha}\partial_{\alpha}\left(\cdot\right) \qquad \int d^{2} \bar{\theta} \left(\cdot\right) = -\frac{1}{4}\partial^{\dot{\alpha}}\partial_{\dot{\alpha}}\left(\cdot\right)' class='latex' /></p>
<p style="text-align:left;">This will be useful later. Total supercovariant derivatives integrate to zero:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B4%7D+x+d%5E%7B4%7D%5Ctheta+D_%7B%5Calpha%7D%5Cleft%28%5Ccdot%5Cright%29+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{4} x d^{4}\theta D_{\alpha}\left(\cdot\right) = 0' title='\displaystyle \int d^{4} x d^{4}\theta D_{\alpha}\left(\cdot\right) = 0' class='latex' /></p>
<p style="text-align:left;">Here we have ignore boundary terms. Integration over all superspace can be expressed as</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B4%7Dx+d%5E%7B2%7D%5Ctheta+d%5E%7B2%7D%5Cbar%7B%5Ctheta%7D%5Cleft%28%5Ccdot%5Cright%29+%3D+%5Cint+d%5E%7B4%7D+x+%5Cleft%28-%5Cfrac%7B1%7D%7B4%7DD%5E%7B2%7D%5Cright%29%5Cleft%28-%5Cfrac%7B1%7D%7B4%7D%5Cbar%7BD%7D%5E%7B2%7D%5Cright%29%5Cleft%28%5Ccdot%5Cright%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{4}x d^{2}\theta d^{2}\bar{\theta}\left(\cdot\right) = \int d^{4} x \left(-\frac{1}{4}D^{2}\right)\left(-\frac{1}{4}\bar{D}^{2}\right)\left(\cdot\right)' title='\displaystyle \int d^{4}x d^{2}\theta d^{2}\bar{\theta}\left(\cdot\right) = \int d^{4} x \left(-\frac{1}{4}D^{2}\right)\left(-\frac{1}{4}\bar{D}^{2}\right)\left(\cdot\right)' class='latex' /></p>
<p style="text-align:left;">Now we turn to chiral superfields. A superfield is a function that is defined on superspace (i.e. it has dependence on the spacetime coordinates and the supercoordinates also). A chiral superfield satisfies the constraint:</p>
<p style="text-align:center;">Either   <img src='http://l.wordpress.com/latex.php?latex=%5Cbar%7BD%7D_%7B%5Cdot%7B%5Calpha%7D%7D+%5Cphi+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\bar{D}_{\dot{\alpha}} \phi = 0' title='\bar{D}_{\dot{\alpha}} \phi = 0' class='latex' />   or   <img src='http://l.wordpress.com/latex.php?latex=D_%7B%5Calpha%7D+%5Cphi+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='D_{\alpha} \phi = 0' title='D_{\alpha} \phi = 0' class='latex' />   but not both.</p>
<p style="text-align:left;">With chiral superfields one can do wonders. For example, sticking to the first choice for constraint defining a chiral superfield,  we have the property</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cbar%7BD%7D%5E%7B2%7DD%5E%7B2%7D%5Cphi+%3D+16+%5CBox+%5Cphi&#038;bg=fff&#038;fg=222&#038;s=0' alt='\bar{D}^{2}D^{2}\phi = 16 \Box \phi' title='\bar{D}^{2}D^{2}\phi = 16 \Box \phi' class='latex' /></p>
<p style="text-align:left;">This is useful when re-writing chiral integrals as integrals over the whole supercoordinates:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d%5E%7B4%7D+x+d%5E%7B2%7D+%5Cphi+%3D+%5Cint+d%5E%7B4%7D+x+%5Cleft%28-%5Cfrac%7BD%5E%7B2%7D%7D%7B4%7D%5Cright%29+%5Cfrac%7B%5Cbar%7BD%7D%5E%7B2%7D+D%5E%7B2%7D%7D%7B16+%5CBox%7D%5Cphi+%3D+%5Cint+d%5E%7B4%7D+x+d%5E%7B4%7D+%5Ctheta+%5Cleft%28-%5Cfrac%7BD%5E%7B2%7D%7D%7B4+%5CBox%7D%5Cright%29+%5Cphi&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d^{4} x d^{2} \phi = \int d^{4} x \left(-\frac{D^{2}}{4}\right) \frac{\bar{D}^{2} D^{2}}{16 \Box}\phi = \int d^{4} x d^{4} \theta \left(-\frac{D^{2}}{4 \Box}\right) \phi' title='\displaystyle \int d^{4} x d^{2} \phi = \int d^{4} x \left(-\frac{D^{2}}{4}\right) \frac{\bar{D}^{2} D^{2}}{16 \Box}\phi = \int d^{4} x d^{4} \theta \left(-\frac{D^{2}}{4 \Box}\right) \phi' class='latex' /></p>
<p style="text-align:left;">We have forgotten about Dirac delta functions for supercoordinates! For a single supercoordinate we define:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+%5Cint+d+%5Ctheta+%5Cdelta%5Cleft%28%5Ctheta+-+%5Ctheta%27+%5Cright%29+f%5Cleft%28%5Ctheta%5Cright%29+%3D+f%5Cleft%28%5Ctheta%27%5Cright%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle \int d \theta \delta\left(\theta - \theta&#039; \right) f\left(\theta\right) = f\left(\theta&#039;\right)' title='\displaystyle \int d \theta \delta\left(\theta - \theta&#039; \right) f\left(\theta\right) = f\left(\theta&#039;\right)' class='latex' /></p>
<p style="text-align:left;">In particular, for the case of the identity function we get</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7B%5Cpartial%7D%7B%5Cpartial+%5Ctheta%7D%5Cdelta%5Cleft%28%5Ctheta+-+%5Ctheta%27+%5Cright%29+%3D+1+%5CRightarrow%5Cdelta%5Cleft%28%5Ctheta+-+%5Ctheta%27+%5Cright%29+%3D+%5Ctheta+-+%5Ctheta%27&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{\partial}{\partial \theta}\delta\left(\theta - \theta&#039; \right) = 1 \Rightarrow\delta\left(\theta - \theta&#039; \right) = \theta - \theta&#039;' title='\displaystyle\frac{\partial}{\partial \theta}\delta\left(\theta - \theta&#039; \right) = 1 \Rightarrow\delta\left(\theta - \theta&#039; \right) = \theta - \theta&#039;' class='latex' /></p>
<p style="text-align:left;">This result can be generalized to the full superspace integral:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7B1%7D%7B16%7D+%5Cpartial%5E%7B%5Calpha%7D%5Cpartial_%7B%5Calpha%7D%5Cpartial%5E%7B%5Cdot%7B%5Cbeta%7D%7D%5Cpartial_%7B%5Cdot%7B%5Cbeta%7D%7D%5Cdelta%5E%7B4%7D%5Cleft%28%5Ctheta_%7B1%7D+-+%5Ctheta_%7B2%7D+%5Cright%29+%3D+1&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{1}{16} \partial^{\alpha}\partial_{\alpha}\partial^{\dot{\beta}}\partial_{\dot{\beta}}\delta^{4}\left(\theta_{1} - \theta_{2} \right) = 1' title='\displaystyle\frac{1}{16} \partial^{\alpha}\partial_{\alpha}\partial^{\dot{\beta}}\partial_{\dot{\beta}}\delta^{4}\left(\theta_{1} - \theta_{2} \right) = 1' class='latex' /></p>
<p style="text-align:left;">(Writing the integral as derivatives as discussed above.) The solution to this equation is</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdelta%5E%7B4%7D%5Cleft%28%5Ctheta_%7B1%7D+-+%5Ctheta_%7B2%7D+%5Cright%29+%3D+%5Cleft%28%5Ctheta_%7B1%7D+-+%5Ctheta_%7B2%7D+%5Cright%29%5E%7B2%7D+%5Cleft%28%5Cbar%7B%5Ctheta%7D_%7B1%7D+-+%5Cbar%7B%5Ctheta%7D_%7B2%7D+%5Cright%29%5E%7B2%7D+%3D+%5Cdelta_%7B12%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\delta^{4}\left(\theta_{1} - \theta_{2} \right) = \left(\theta_{1} - \theta_{2} \right)^{2} \left(\bar{\theta}_{1} - \bar{\theta}_{2} \right)^{2} = \delta_{12}' title='\delta^{4}\left(\theta_{1} - \theta_{2} \right) = \left(\theta_{1} - \theta_{2} \right)^{2} \left(\bar{\theta}_{1} - \bar{\theta}_{2} \right)^{2} = \delta_{12}' class='latex' /></p>
<p style="text-align:left;">We can mention some properties related to this delta function:</p>
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		<title>Solving equations of motions in some gravity background</title>
		<link>http://indexguy.wordpress.com/2008/08/31/solving-equations-of-motions-in-some-gravity-background/</link>
		<comments>http://indexguy.wordpress.com/2008/08/31/solving-equations-of-motions-in-some-gravity-background/#comments</comments>
		<pubDate>Mon, 01 Sep 2008 01:37:19 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[AdS/CFT]]></category>
		<category><![CDATA[String Theory]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=213</guid>
		<description><![CDATA[I would like to consider the gravity background:

with the case that  We saw previously that the equations of motion were given by:
     and     
Now we take the warp factor to have the form . Then we have

We will introduce a new symbol,
     with  a function of the worldsheet coordinates.
The differential equation now looks [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=213&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>I would like to consider the gravity background:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+A+dx%5E2+%2B+B+dr%5E2+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = A dx^2 + B dr^2 ,' title='ds^2 = A dx^2 + B dr^2 ,' class='latex' /></p>
<p>with the case that <img src='http://l.wordpress.com/latex.php?latex=A+%3D+B%5E%7B-1%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='A = B^{-1}.' title='A = B^{-1}.' class='latex' /> We saw previously that the equations of motion were given by:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7Bi%7D%5Cleft%28A%5Cpartial_%7Bi%7Dx%5Ea%5Cright%29+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{i}\left(A\partial_{i}x^a\right) = 0' title='\partial_{i}\left(A\partial_{i}x^a\right) = 0' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=-2%5Cpartial_%7Bi%7D%5E%7B2%7Dr+%3D+%5Cdisplaystyle%5Cfrac%7Bd+%5Cleft%28%5Cln%7BB%7D%5Cright%29%7D%7Bd+r%7D%5Cleft%28-%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dy%5E%7Ba%7D%5Cpartial_%7Bi%7Dy%5E%7Bb%7D+%2B%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-2\partial_{i}^{2}r = \displaystyle\frac{d \left(\ln{B}\right)}{d r}\left(-\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} +\partial_{i}r\partial_{i}r\right).' title='-2\partial_{i}^{2}r = \displaystyle\frac{d \left(\ln{B}\right)}{d r}\left(-\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} +\partial_{i}r\partial_{i}r\right).' class='latex' /></p>
<p>Now we take the warp factor to have the form <img src='http://l.wordpress.com/latex.php?latex=B+%3D+r%5E%7B%5Cbeta%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='B = r^{\beta}' title='B = r^{\beta}' class='latex' />. Then we have</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=-2+r+%5Cpartial_%7Bi%7D%5E%7B2%7Dr+%3D+%5Cbeta%5Cdisplaystyle%5Cleft%28-%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dy%5E%7Ba%7D%5Cpartial_%7Bi%7Dy%5E%7Bb%7D+%2B%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-2 r \partial_{i}^{2}r = \beta\displaystyle\left(-\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} +\partial_{i}r\partial_{i}r\right).' title='-2 r \partial_{i}^{2}r = \beta\displaystyle\left(-\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} +\partial_{i}r\partial_{i}r\right).' class='latex' /></p>
<p>We will introduce a new symbol,</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dy%5E%7Ba%7D%5Cpartial_%7Bi%7Dy%5E%7Bb%7D+%3D+-W%5E%7B2%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} = -W^{2}' title='\eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} = -W^{2}' class='latex' />     with <img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle+W%28u_%7B1%7D%2C+u_%7B2%7D%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle W(u_{1}, u_{2})' title='\displaystyle W(u_{1}, u_{2})' class='latex' /> a function of the worldsheet coordinates.</p>
<p>The differential equation now looks like:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=2+r+%5Cpartial_%7Bi%7D%5E%7B2%7Dr+%2B+%5Cbeta+%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr+%3D+%5Cbeta+W%5E%7B2%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='2 r \partial_{i}^{2}r + \beta \partial_{i}r\partial_{i}r = \beta W^{2}.' title='2 r \partial_{i}^{2}r + \beta \partial_{i}r\partial_{i}r = \beta W^{2}.' class='latex' /></p>
<p>We now assume that <img src='http://l.wordpress.com/latex.php?latex=r&#038;bg=fff&#038;fg=222&#038;s=0' alt='r' title='r' class='latex' /> can be factored into functions of each coordinate, <img src='http://l.wordpress.com/latex.php?latex=r+%3D+T%28u_%7B1%7D%29+S%28u_%7B2%7D%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='r = T(u_{1}) S(u_{2})' title='r = T(u_{1}) S(u_{2})' class='latex' />. Then we can solve this PDE when</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=k%5E2+%3D+%5Cdisplaystyle%5Cfrac%7B%5Cbeta+W%5E2%7D%7B2+T%5E%7B2%7D+S%5E%7B2%7D%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='k^2 = \displaystyle\frac{\beta W^2}{2 T^{2} S^{2}}' title='k^2 = \displaystyle\frac{\beta W^2}{2 T^{2} S^{2}}' class='latex' />     with <img src='http://l.wordpress.com/latex.php?latex=k&#038;bg=fff&#038;fg=222&#038;s=0' alt='k' title='k' class='latex' /> a constant.</p>
<p>Separation of variables gives the following differential equation:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7Bd%5E2+Y%7D%7Bdu_%7Bi%7D%5E2%7D+%2B+%5Calpha+%5Cleft%28%5Cdisplaystyle%5Cfrac%7Bd+Y%7D%7Bd+u_%7Bi%7D%7D%5Cright%29%5E%7B2%7D+%3D+k_%7Bi%7D%5E%7B2%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{d^2 Y}{du_{i}^2} + \alpha \left(\displaystyle\frac{d Y}{d u_{i}}\right)^{2} = k_{i}^{2},' title='\displaystyle\frac{d^2 Y}{du_{i}^2} + \alpha \left(\displaystyle\frac{d Y}{d u_{i}}\right)^{2} = k_{i}^{2},' class='latex' /></p>
<p>with</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Calpha+%3D+1+%2B+%5Cdisplaystyle%5Cfrac%7B%5Cbeta%7D%7B2%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\alpha = 1 + \displaystyle\frac{\beta}{2}' title='\alpha = 1 + \displaystyle\frac{\beta}{2}' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=T+%3D+%5Cexp%7BY%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='T = \exp{Y}.' title='T = \exp{Y}.' class='latex' /></p>
<p>Inserting this into Mathematica gives:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=Y%28u%29+%3D+C_%7B1%7D+%2B+%5Cdisplaystyle%5Cfrac%7B1%7D%7B%5Calpha%7D%5Cln%7B%5Cleft%28%5Ccosh%7B%5Cleft%28k_%7Bi%7D%5Csqrt%7B%5Calpha%7D%5Cleft%5Bu_%7Bi%7D+%2B+C_%7B2%7D%5Cright%5D%5Cright%29%7D%5Cright%29%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='Y(u) = C_{1} + \displaystyle\frac{1}{\alpha}\ln{\left(\cosh{\left(k_{i}\sqrt{\alpha}\left[u_{i} + C_{2}\right]\right)}\right)}.' title='Y(u) = C_{1} + \displaystyle\frac{1}{\alpha}\ln{\left(\cosh{\left(k_{i}\sqrt{\alpha}\left[u_{i} + C_{2}\right]\right)}\right)}.' class='latex' />     which means     <img src='http://l.wordpress.com/latex.php?latex=T%28u%29+%3D+C_%7B1%7D+%5Cleft%28%5Ccosh%7B%5Cleft%28k_%7Bi%7D%5Csqrt%7B%5Calpha%7D%5Cleft%5Bu_%7Bi%7D+%2B+C_%7B2%7D%5Cright%5D%5Cright%29%7D+%5Cright%29%5E%7B1%2F%5Calpha%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='T(u) = C_{1} \left(\cosh{\left(k_{i}\sqrt{\alpha}\left[u_{i} + C_{2}\right]\right)} \right)^{1/\alpha}.' title='T(u) = C_{1} \left(\cosh{\left(k_{i}\sqrt{\alpha}\left[u_{i} + C_{2}\right]\right)} \right)^{1/\alpha}.' class='latex' /></p>
<p>Notice that the case <img src='http://l.wordpress.com/latex.php?latex=%5Cbeta+%3D+-2&#038;bg=fff&#038;fg=222&#038;s=0' alt='\beta = -2' title='\beta = -2' class='latex' /> is interesting: for the constraints we have used the solution is an exponential function of a quadratic polynomial.</p>
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		<title>A curved lagrangian in terms of a flat one</title>
		<link>http://indexguy.wordpress.com/2008/08/22/a-curved-lagrangian-in-terms-of-a-flat-one/</link>
		<comments>http://indexguy.wordpress.com/2008/08/22/a-curved-lagrangian-in-terms-of-a-flat-one/#comments</comments>
		<pubDate>Fri, 22 Aug 2008 15:24:56 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Relativity]]></category>
		<category><![CDATA[String Theory]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=184</guid>
		<description><![CDATA[Let us consider the following gravitational background:

and the Polyakov lagrangian in conformal gauge with Euclidean Lorentzian signature:

The Euler-Lagrange equations can be found to be:
     and     
We look at this and think how can we make these equations simpler. The first equation can be solved with:

This is a &#8220;T-duality&#8221; transformation. For the second equation we see [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=184&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Let us consider the following gravitational background:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+A%28r%29%5Ceta_%7Bab%7Ddx%5Ea+dx%5Eb+%2B+B%28r%29dr%5E2%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = A(r)\eta_{ab}dx^a dx^b + B(r)dr^2,' title='ds^2 = A(r)\eta_{ab}dx^a dx^b + B(r)dr^2,' class='latex' /></p>
<p>and the Polyakov lagrangian in conformal gauge with <span style="text-decoration:line-through;">Euclidean</span> Lorentzian signature:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=L_%7Bp%7D+%3D+A+%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dx%5E%7Ba%7D%5Cpartial_%7Bi%7Dx%5E%7Bb%7D+%2B+B%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{p} = A \eta_{ab}\partial_{i}x^{a}\partial_{i}x^{b} + B\partial_{i}r\partial_{i}r.' title='L_{p} = A \eta_{ab}\partial_{i}x^{a}\partial_{i}x^{b} + B\partial_{i}r\partial_{i}r.' class='latex' /></p>
<p>The Euler-Lagrange equations can be found to be:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7Bi%7D%5Cleft%28A%5Cpartial_%7Bi%7Dx%5Ea%5Cright%29+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{i}\left(A\partial_{i}x^a\right) = 0' title='\partial_{i}\left(A\partial_{i}x^a\right) = 0' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=2B%5Cpartial_%7Bi%7D%5E%7B2%7Dr+%3D+%5Cdisplaystyle%5Cfrac%7Bd+A%7D%7Bd+r%7D+%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dx%5E%7Ba%7D%5Cpartial_%7Bi%7Dx%5E%7Bb%7D+-+B%5Cdisplaystyle%5Cfrac%7Bd+%5Cleft%28%5Cln%7BB%7D%5Cright%29%7D%7Bd+r%7D%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='2B\partial_{i}^{2}r = \displaystyle\frac{d A}{d r} \eta_{ab}\partial_{i}x^{a}\partial_{i}x^{b} - B\displaystyle\frac{d \left(\ln{B}\right)}{d r}\partial_{i}r\partial_{i}r.' title='2B\partial_{i}^{2}r = \displaystyle\frac{d A}{d r} \eta_{ab}\partial_{i}x^{a}\partial_{i}x^{b} - B\displaystyle\frac{d \left(\ln{B}\right)}{d r}\partial_{i}r\partial_{i}r.' class='latex' /></p>
<p>We look at this and think how can we make these equations simpler. The first equation can be solved with:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7Bi%7D+y%5E%7Ba%7D+%3D+A%5Cepsilon_%7Bij%7D%5Cpartial_%7Bj%7Dx%5E%7Ba%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{i} y^{a} = A\epsilon_{ij}\partial_{j}x^{a}.' title='\partial_{i} y^{a} = A\epsilon_{ij}\partial_{j}x^{a}.' class='latex' /></p>
<p>This is a &#8220;T-duality&#8221; transformation. For the second equation we see that if <img src='http://l.wordpress.com/latex.php?latex=A+%3D+B%5E%7B-1%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='A = B^{-1}' title='A = B^{-1}' class='latex' /> then we get</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7Bd%5Cleft%28%5Cln%7BB%7D%5Cright%29%7D%7Bd+r%7D+%3D+%5Cdisplaystyle%5Cfrac%7B%5Cpartial_%7Bi%7D%5E%7B2%7Dr%7D%7BL_%7Bf%7D%28y%5E%7Ba%7D%2C+r%29%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{d\left(\ln{B}\right)}{d r} = \displaystyle\frac{\partial_{i}^{2}r}{L_{f}(y^{a}, r)},' title='\displaystyle\frac{d\left(\ln{B}\right)}{d r} = \displaystyle\frac{\partial_{i}^{2}r}{L_{f}(y^{a}, r)},' class='latex' /></p>
<p>with <img src='http://l.wordpress.com/latex.php?latex=L_%7Bf%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{f}' title='L_{f}' class='latex' /> the flat-space Polyakov lagrangian in terms of the new coordinates <img src='http://l.wordpress.com/latex.php?latex=y%5E%7Ba%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='y^{a}' title='y^{a}' class='latex' />:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=L_%7Bf%7D%5Cleft%28y%5E%7Ba%7D%2Cr%5Cright%29+%3D+%5Ceta_%7Bab%7D%5Cpartial_%7Bi%7Dy%5E%7Ba%7D%5Cpartial_%7Bi%7Dy%5E%7Bb%7D+%2B+%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{f}\left(y^{a},r\right) = \eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} + \partial_{i}r\partial_{i}r.' title='L_{f}\left(y^{a},r\right) = \eta_{ab}\partial_{i}y^{a}\partial_{i}y^{b} + \partial_{i}r\partial_{i}r.' class='latex' /></p>
<p>We can integrate this equation to find an expression for <img src='http://l.wordpress.com/latex.php?latex=B&#038;bg=fff&#038;fg=222&#038;s=0' alt='B' title='B' class='latex' /> in terms of the solutions of the equations of motion and the flat-space lagrangian:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=B%28r%29+%3D+B%28r_%7B0%7D%29+%5Cexp%7B%5Cleft%28-2%5Cdisplaystyle%5Cint_%7Br_%7B0%7D%7D%5E%7Br%7Dd%5Ctilde%7Br%7D%5Cdisplaystyle%5Cfrac%7B%5Cpartial%5E%7B2%7D%5Ctilde%7Br%7D%7D%7BL_%7Bf%7D%28%5Ctilde%7By%7D%5E%7Ba%7D+%2C%5Ctilde%7Br%7D%29%7D%5Cright%29%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='B(r) = B(r_{0}) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{L_{f}(\tilde{y}^{a} ,\tilde{r})}\right)}.' title='B(r) = B(r_{0}) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{L_{f}(\tilde{y}^{a} ,\tilde{r})}\right)}.' class='latex' /></p>
<p>Then, pluging this back into the classical action we get</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=S+%3D+%5Cdisplaystyle%5Cint+d%5E2+u+B%28r_%7B0%7D%29+L_%7Bf%7D%28y%5E%7Ba%7D%2C+r%29+%5Cexp%7B%5Cleft%28-2%5Cdisplaystyle%5Cint_%7Br_%7B0%7D%7D%5E%7Br%7Dd%5Ctilde%7Br%7D%5Cdisplaystyle%5Cfrac%7B%5Cpartial%5E%7B2%7D%5Ctilde%7Br%7D%7D%7BL_%7Bf%7D%28%5Ctilde%7By%7D%5E%7Ba%7D%2C+%5Ctilde%7Br%7D%29%7D%5Cright%29%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='S = \displaystyle\int d^2 u B(r_{0}) L_{f}(y^{a}, r) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{L_{f}(\tilde{y}^{a}, \tilde{r})}\right)}.' title='S = \displaystyle\int d^2 u B(r_{0}) L_{f}(y^{a}, r) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{L_{f}(\tilde{y}^{a}, \tilde{r})}\right)}.' class='latex' /></p>
<p>Finally we can write</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=d%5Ctilde%7Br%7D+%3D+%5Cpartial_%7Bj%7D%5Ctilde%7Br%7D+du_%7Bj%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='d\tilde{r} = \partial_{j}\tilde{r} du_{j},' title='d\tilde{r} = \partial_{j}\tilde{r} du_{j},' class='latex' /></p>
<p>so we can write the expression in the exponential as a sum of integrals over the worldsheet coordinates.</p>
<p>On the other hand, if instead we have <img src='http://l.wordpress.com/latex.php?latex=A+%3D+B&#038;bg=fff&#038;fg=222&#038;s=0' alt='A = B' title='A = B' class='latex' /> then we can write:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=A%28r%29+%3D+A%28r_%7B0%7D%29+%3D+%5Cexp%7B%5Cleft%28-2%5Cdisplaystyle%5Cint_%7Br_%7B0%7D%7D%5E%7Br%7Dd%5Ctilde%7Br%7D%5Cdisplaystyle%5Cfrac%7B%5Cpartial%5E%7B2%7D%5Ctilde%7Br%7D%7D%7BK_%7Bf%7D%28%5Ctilde%7Bx%7D%5E%7Ba%7D+%2C%5Ctilde%7Br%7D%29%7D%5Cright%29%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='A(r) = A(r_{0}) = \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{K_{f}(\tilde{x}^{a} ,\tilde{r})}\right)},' title='A(r) = A(r_{0}) = \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{K_{f}(\tilde{x}^{a} ,\tilde{r})}\right)},' class='latex' /></p>
<p>with</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=K_%7Bf%7D%28x%5E%7Ba%7D+%2Cr%29+%3D+2%5Cpartial_%7Bi%7Dr%5Cpartial_%7Bi%7Dr+-+L_%7Bf%7D%28x%5E%7Ba%7D+%2C+r%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='K_{f}(x^{a} ,r) = 2\partial_{i}r\partial_{i}r - L_{f}(x^{a} , r).' title='K_{f}(x^{a} ,r) = 2\partial_{i}r\partial_{i}r - L_{f}(x^{a} , r).' class='latex' /></p>
<p>The lagrangian can be writen as</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=L_%7Bp%7D+%3D+A%28r_%7B0%7D%29+L_%7Bf%7D%28x%5E%7Ba%7D%2C+r%29+%5Cexp%7B%5Cleft%28-2%5Cdisplaystyle%5Cint_%7Br_%7B0%7D%7D%5E%7Br%7Dd%5Ctilde%7Br%7D%5Cdisplaystyle%5Cfrac%7B%5Cpartial%5E%7B2%7D%5Ctilde%7Br%7D%7D%7BK_%7Bf%7D%28%5Ctilde%7Bx%7D%5E%7Ba%7D+%2C%5Ctilde%7Br%7D%29%7D%5Cright%29%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{p} = A(r_{0}) L_{f}(x^{a}, r) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{K_{f}(\tilde{x}^{a} ,\tilde{r})}\right)}.' title='L_{p} = A(r_{0}) L_{f}(x^{a}, r) \exp{\left(-2\displaystyle\int_{r_{0}}^{r}d\tilde{r}\displaystyle\frac{\partial^{2}\tilde{r}}{K_{f}(\tilde{x}^{a} ,\tilde{r})}\right)}.' class='latex' /></p>
<p>We have found an expression for the classical lagragian in some (not-so) arbitrary gravitational background in terms of the coordinates and the flat-space lagrangian. The problem is we do not get any information about the solution for the equations of motion.</p>
<p style="text-align:left;">
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		<title>Ego-breaking</title>
		<link>http://indexguy.wordpress.com/2008/08/12/ego-breaking/</link>
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		<pubDate>Wed, 13 Aug 2008 01:33:01 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Organizational]]></category>

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		<description><![CDATA[The hardest part of research is to overcome one&#8217;s ego and know when one&#8217;s ideas are leading nowhere. Also, to accept advice from others.
       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=182&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>The hardest part of research is to overcome one&#8217;s ego and know when one&#8217;s ideas are leading nowhere. Also, to accept advice from others.</p>
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		<title>Minimal area in arbitrary background (I)</title>
		<link>http://indexguy.wordpress.com/2008/08/07/minimal-area-in-arbitrary-background-i/</link>
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		<pubDate>Thu, 07 Aug 2008 17:55:01 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Gravity]]></category>
		<category><![CDATA[String Theory]]></category>

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		<description><![CDATA[Let us start with the following background metric:

where the functions  and  are functions of the extra coordinate . The case of anti-de Sitter space corresponds to

Under the &#8220;T-duality&#8221; transformation
   and   
the metric in the dual space takes the form

but now
   and   
Since we can always bring the metric in this form, we [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=149&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Let us start with the following background metric:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+A%5Ceta_%7Bmn%7Ddx%5Em+dx%5En+%2B+Bdr%5E2+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = A\eta_{mn}dx^m dx^n + Bdr^2 ,' title='ds^2 = A\eta_{mn}dx^m dx^n + Bdr^2 ,' class='latex' /></p>
<p>where the functions <img src='http://l.wordpress.com/latex.php?latex=A&#038;bg=fff&#038;fg=222&#038;s=0' alt='A' title='A' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=B&#038;bg=fff&#038;fg=222&#038;s=0' alt='B' title='B' class='latex' /> are functions of the extra coordinate <img src='http://l.wordpress.com/latex.php?latex=r&#038;bg=fff&#038;fg=222&#038;s=0' alt='r' title='r' class='latex' />. The case of anti-de Sitter space corresponds to</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=A+%3D+B+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='A = B = \displaystyle\frac{R^2}{r^2}.' title='A = B = \displaystyle\frac{R^2}{r^2}.' class='latex' /></p>
<p>Under the &#8220;T-duality&#8221; transformation</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7Ba%7Dy%5Em+%3D+i+A+%5Cepsilon_%7Bab%7D%5Cpartial_%7Bb%7Dx%5Em&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{a}y^m = i A \epsilon_{ab}\partial_{b}x^m' title='\partial_{a}y^m = i A \epsilon_{ab}\partial_{b}x^m' class='latex' />   and   <img src='http://l.wordpress.com/latex.php?latex=%5Crho+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\rho = \displaystyle\frac{R^2}{r}' title='\rho = \displaystyle\frac{R^2}{r}' class='latex' /></p>
<p>the metric in the dual space takes the form</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Ctilde%7BA%7D%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+%5Ctilde%7BB%7Dd%5Crho%5E2+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \tilde{A}\eta_{mn}dy^m dy^n + \tilde{B}d\rho^2 ,' title='ds^2 = \tilde{A}\eta_{mn}dy^m dy^n + \tilde{B}d\rho^2 ,' class='latex' /></p>
<p>but now</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Ctilde%7BA%7D+%3D+%5Cleft%5BA%28%5Crho%29%5Cright%5D%5E%7B-1%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\tilde{A} = \left[A(\rho)\right]^{-1}' title='\tilde{A} = \left[A(\rho)\right]^{-1}' class='latex' />   and   <img src='http://l.wordpress.com/latex.php?latex=%5Ctilde%7BB%7D+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E4%7D%7B%5Crho%5E4%7DB%28%5Crho%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\tilde{B} = \displaystyle\frac{R^4}{\rho^4}B(\rho).' title='\tilde{B} = \displaystyle\frac{R^4}{\rho^4}B(\rho).' class='latex' /></p>
<p>Since we can always bring the metric in this form, we will just consider the initial case and see what can we do with it. Note that it could be the case that the change of variables between <img src='http://l.wordpress.com/latex.php?latex=%28r%2C%5Crho%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(r,\rho)' title='(r,\rho)' class='latex' /> could be of the general form</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Crho+%3D+Ar&#038;bg=fff&#038;fg=222&#038;s=0' alt='\rho = Ar' title='\rho = Ar' class='latex' />   which means   <img src='http://l.wordpress.com/latex.php?latex=dr%5E2+%3D+%5Cleft%28r%5Cdisplaystyle%5Cfrac%7B%5Cpartial+A%7D%7B%5Cpartial+r%7D+%2B+A%5Cright%29%5E%7B-2%7Dd%5Crho%5E2+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='dr^2 = \left(r\displaystyle\frac{\partial A}{\partial r} + A\right)^{-2}d\rho^2 .' title='dr^2 = \left(r\displaystyle\frac{\partial A}{\partial r} + A\right)^{-2}d\rho^2 .' class='latex' /></p>
<p>This case could be more complicated&#8230; For now we will just stick with the first change of variables introduced.</p>
<p><span id="more-149"></span>I will consider a classical string, and I will set one of the (spatial) coordinates equal to zero and work with a static gauge: the other two spatial coordinates describe the worldsheet of the strings. I am interested in a configuration very similar to that on the Alday-Maldacena paper. The one thing I could change is to allow the polygon where the worldsheet end to be time-like instead of light-like. This is achieved by setting</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=x_0+%3D+%5Cpm+%5CUpsilon_%7B1%2C2%7D+x_%7B1%2C2%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='x_0 = \pm \Upsilon_{1,2} x_{1,2},' title='x_0 = \pm \Upsilon_{1,2} x_{1,2},' class='latex' /></p>
<p>with <img src='http://l.wordpress.com/latex.php?latex=%5CUpsilon_%7B1%2C2%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='\Upsilon_{1,2}' title='\Upsilon_{1,2}' class='latex' /> being a positive real number that is greater than unity. Our metric has signature <img src='http://l.wordpress.com/latex.php?latex=%28-%2B%2B...%2B%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(-++...+)' title='(-++...+)' class='latex' />.</p>
<p>In anticipation we will define the following symbols:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=x_0+%5Cequiv+X+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='x_0 \equiv X ,' title='x_0 \equiv X ,' class='latex' />     <img src='http://l.wordpress.com/latex.php?latex=X_%7Bj%7D+%3D+%5Cpartial_%7Bj%7DX+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='X_{j} = \partial_{j}X ,' title='X_{j} = \partial_{j}X ,' class='latex' />     <img src='http://l.wordpress.com/latex.php?latex=r_%7Bj%7D+%3D+%5Cpartial_%7Bj%7Dr+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='r_{j} = \partial_{j}r ,' title='r_{j} = \partial_{j}r ,' class='latex' />     <img src='http://l.wordpress.com/latex.php?latex=F_%7Bij%7D+%3D+r_%7Bi%7DX_%7Bj%7D-r_%7Bj%7DX_%7Bi%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='F_{ij} = r_{i}X_{j}-r_{j}X_{i},' title='F_{ij} = r_{i}X_{j}-r_{j}X_{i},' class='latex' /></p>
<p>with the index <img src='http://l.wordpress.com/latex.php?latex=j&#038;bg=fff&#038;fg=222&#038;s=0' alt='j' title='j' class='latex' /> taking values of 1 and 2. Our coordinate vector in the static gauge looks like:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=C%5EM+%3D+%5Cleft%28X%2C+u_1%2C+u_2%2C+0%2C+r%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^M = \left(X, u_1, u_2, 0, r\right).' title='C^M = \left(X, u_1, u_2, 0, r\right).' class='latex' /></p>
<p>The Nambu-Goto action involves the determinant of the induced metric,</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=-G+%3D+%5Cleft%28%5Cpartial_%7B1%7D+C+%5Ccdot+%5Cpartial_%7B2%7D+C%5Cright%29%5E2+-+%5Cleft%28%5Cpartial_%7B1%7DC%5Cright%29%5E2+%5Cleft%28%5Cpartial_%7B2%7DC%5Cright%29%5E2+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-G = \left(\partial_{1} C \cdot \partial_{2} C\right)^2 - \left(\partial_{1}C\right)^2 \left(\partial_{2}C\right)^2 .' title='-G = \left(\partial_{1} C \cdot \partial_{2} C\right)^2 - \left(\partial_{1}C\right)^2 \left(\partial_{2}C\right)^2 .' class='latex' /></p>
<p>Evaluating we get:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cleft%28%5Cpartial_%7B1%7D+C+%5Ccdot+%5Cpartial_%7B2%7D+C%5Cright%29%5E2+%3D+-AX_%7B1%7DX_%7B2%7D+%2B+Br_%7B1%7Dr_%7B2%7D+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\left(\partial_{1} C \cdot \partial_{2} C\right)^2 = -AX_{1}X_{2} + Br_{1}r_{2} ,' title='\left(\partial_{1} C \cdot \partial_{2} C\right)^2 = -AX_{1}X_{2} + Br_{1}r_{2} ,' class='latex' />     <img src='http://l.wordpress.com/latex.php?latex=+%5Cleft%28%5Cpartial_%7B1%7DC%5Cright%29%5E2+%3D+A%5Cleft%281+-+X_%7B1%7D%5E2+%5Cright%29%2BBr_%7B1%7D%5E%7B2%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt=' \left(\partial_{1}C\right)^2 = A\left(1 - X_{1}^2 \right)+Br_{1}^{2}' title=' \left(\partial_{1}C\right)^2 = A\left(1 - X_{1}^2 \right)+Br_{1}^{2}' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=+%5Cleft%28%5Cpartial_%7B2%7DC%5Cright%29%5E2+%3D+A%5Cleft%281+-+X_%7B2%7D%5E2+%5Cright%29%2BBr_%7B2%7D%5E%7B2%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt=' \left(\partial_{2}C\right)^2 = A\left(1 - X_{2}^2 \right)+Br_{2}^{2}.' title=' \left(\partial_{2}C\right)^2 = A\left(1 - X_{2}^2 \right)+Br_{2}^{2}.' class='latex' /></p>
<p>Then, after plugging all these into the expression for the determinant we get:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=-G+%3D+-A%5Cleft%5B+A%5Cleft%281+-+X_%7B1%7D%5E2+-+X_%7B2%7D%5E2+%5Cright%29+%2B+B%5Cleft%28r_%7B1%7D%5E2+%2B+r_%7B2%7D%5E2+-+F_%7B12%7D%5E2%5Cright%29+%5Cright%5D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-G = -A\left[ A\left(1 - X_{1}^2 - X_{2}^2 \right) + B\left(r_{1}^2 + r_{2}^2 - F_{12}^2\right) \right].' title='-G = -A\left[ A\left(1 - X_{1}^2 - X_{2}^2 \right) + B\left(r_{1}^2 + r_{2}^2 - F_{12}^2\right) \right].' class='latex' /></p>
<p>We see a factor of <img src='http://l.wordpress.com/latex.php?latex=i&#038;bg=fff&#038;fg=222&#038;s=0' alt='i' title='i' class='latex' /> popping out of the action. This tells us that the worldsheet has Euclidean signature.</p>
<p>For convenience we will define</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=J+%3D+A%5Cleft%281+-+X_%7B1%7D%5E2+-+X_%7B2%7D%5E2+%5Cright%29+%2B+B%5Cleft%28r_%7B1%7D%5E2+%2B+r_%7B2%7D%5E2+-+F_%7B12%7D%5E2%5Cright%29+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='J = A\left(1 - X_{1}^2 - X_{2}^2 \right) + B\left(r_{1}^2 + r_{2}^2 - F_{12}^2\right) .' title='J = A\left(1 - X_{1}^2 - X_{2}^2 \right) + B\left(r_{1}^2 + r_{2}^2 - F_{12}^2\right) .' class='latex' /></p>
<p>The lagrangian then looks like:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=L_%7BNG%7D+%3D+i+%5Csqrt%7BAJ%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{NG} = i \sqrt{AJ}.' title='L_{NG} = i \sqrt{AJ}.' class='latex' /></p>
<p>Let us now look at the equations of motion for the fields <img src='http://l.wordpress.com/latex.php?latex=X&#038;bg=fff&#038;fg=222&#038;s=0' alt='X' title='X' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=r&#038;bg=fff&#038;fg=222&#038;s=0' alt='r' title='r' class='latex' />. The first field is a bit more simpler:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7B%5Cpartial+L_%7BNG%7D%7D%7B%5Cpartial+X%7D+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{\partial L_{NG}}{\partial X} = 0' title='\displaystyle\frac{\partial L_{NG}}{\partial X} = 0' class='latex' />     which implies     <img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7Bj%7D%5Cdisplaystyle%5Cfrac%7B%5Cpartial+L_%7BNG%7D%7D%7B%5Cpartial+X_%7Bj%7D%7D+%3D+0.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{j}\displaystyle\frac{\partial L_{NG}}{\partial X_{j}} = 0.' title='\partial_{j}\displaystyle\frac{\partial L_{NG}}{\partial X_{j}} = 0.' class='latex' /></p>
<p>This is the expression for a two-dimensional vector that has vanishing divergence. Then it follows that the components of this vector must be of the form:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=V_%7B1%7D+%3D+%5Cpartial_%7B2%7DY+%5Cequiv+Y_2&#038;bg=fff&#038;fg=222&#038;s=0' alt='V_{1} = \partial_{2}Y \equiv Y_2' title='V_{1} = \partial_{2}Y \equiv Y_2' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=V_%7B2%7D+%3D+-%5Cpartial_%7B1%7DY+%5Cequiv+-Y_1+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='V_{2} = -\partial_{1}Y \equiv -Y_1 ,' title='V_{2} = -\partial_{1}Y \equiv -Y_1 ,' class='latex' /></p>
<p>for some other field <img src='http://l.wordpress.com/latex.php?latex=Y&#038;bg=fff&#038;fg=222&#038;s=0' alt='Y' title='Y' class='latex' /> that is a function of both worldsheet coordinates. Note that adding a constant to <img src='http://l.wordpress.com/latex.php?latex=Y&#038;bg=fff&#038;fg=222&#038;s=0' alt='Y' title='Y' class='latex' /> does not affect the equations of motion, so it may correspond to some coordinate with a shift symmetry. Let us look at the conjugate momenta:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7B%5Cpartial+L_%7BNG%7D%7D%7B%5Cpartial+X_1%7D+%5Cequiv+Y_2+%3D+K%5Cleft%28-AX_1+%2B+BF_%7B12%7Dr_2+%5Cright%29+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{\partial L_{NG}}{\partial X_1} \equiv Y_2 = K\left(-AX_1 + BF_{12}r_2 \right) ,' title='\displaystyle\frac{\partial L_{NG}}{\partial X_1} \equiv Y_2 = K\left(-AX_1 + BF_{12}r_2 \right) ,' class='latex' />     and     <img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7B%5Cpartial+L_%7BNG%7D%7D%7B%5Cpartial+X_2%7D+%5Cequiv+-Y_1+%3D+-K%5Cleft%28AX_2+%2B+BF_%7B12%7Dr_1+%5Cright%29+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{\partial L_{NG}}{\partial X_2} \equiv -Y_1 = -K\left(AX_2 + BF_{12}r_1 \right) .' title='\displaystyle\frac{\partial L_{NG}}{\partial X_2} \equiv -Y_1 = -K\left(AX_2 + BF_{12}r_1 \right) .' class='latex' /></p>
<p>We have denoted</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=K+%3D+%5Csqrt%7B%5Cdisplaystyle%5Cfrac%7BA%7D%7BJ%7D%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='K = \sqrt{\displaystyle\frac{A}{J}}.' title='K = \sqrt{\displaystyle\frac{A}{J}}.' class='latex' /></p>
<p>One can see that the ratio of the conjugate momenta has a nice form:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7BY_2%7D%7BY_1%7D+%3D+%5Cdisplaystyle%5Cfrac%7BBF_%7B12%7Dr_2+-+AX_1%7D%7BBF_%7B12%7Dr_1+%2B+AX_2%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{Y_2}{Y_1} = \displaystyle\frac{BF_{12}r_2 - AX_1}{BF_{12}r_1 + AX_2}.' title='\displaystyle\frac{Y_2}{Y_1} = \displaystyle\frac{BF_{12}r_2 - AX_1}{BF_{12}r_1 + AX_2}.' class='latex' /></p>
<p>One can also use this expression to write the ratio of the warp functions in terms of derivatives of the fields:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7BA%7D%7BB%7D+%3D+%5Cdisplaystyle%5Cfrac%7BF_%7B12%7D%5Cleft%28r_2+Y_1+-+r_1+Y_2+%5Cright%29%7D%7BY_1+X_1+%2B+Y_2+X_2%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{A}{B} = \displaystyle\frac{F_{12}\left(r_2 Y_1 - r_1 Y_2 \right)}{Y_1 X_1 + Y_2 X_2}.' title='\displaystyle\frac{A}{B} = \displaystyle\frac{F_{12}\left(r_2 Y_1 - r_1 Y_2 \right)}{Y_1 X_1 + Y_2 X_2}.' class='latex' /></p>
<p>We see that the metric would blow up when the fields <img src='http://l.wordpress.com/latex.php?latex=%28X%2CY%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(X,Y)' title='(X,Y)' class='latex' /> have orthogonal gradients.</p>
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		<title>Some progress towards something</title>
		<link>http://indexguy.wordpress.com/2008/08/04/some-progress-towards-something/</link>
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		<pubDate>Tue, 05 Aug 2008 00:43:10 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Relativity]]></category>
		<category><![CDATA[String Theory]]></category>

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		<description><![CDATA[On Thursday night I was reading Polyakov&#8217;s contribution to the book 50 years of Yang-Mills theory. This is my version of a bed time story.  
Polyakov mentions some of his earlier work and how he solved different problems. I actually got tired after a while, and decided to work and solve my own problem. [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=126&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>On Thursday night I was reading Polyakov&#8217;s contribution to the book <em>50 years of Yang-Mills theory</em>. This is my version of a bed time story. <img src='http://s.wordpress.com/wp-includes/images/smilies/icon_wink.gif' alt=';-)' class='wp-smiley' /> </p>
<p>Polyakov mentions some of his earlier work and how he solved different problems. I actually got tired after a while, and decided to work and solve my own problem. I had been sort of running away from it with feelings of overwhelming difficulty. There is also a chance that reading this <a href="http://golem.ph.utexas.edu/string/archives/000444.html">post</a> on the (now dead) string coffee table provided some motivation. In any case, here we go&#8230;</p>
<p><span id="more-126"></span>Let us consider the following metric in 5-dimensional spacetime:
</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+A%28r%29%5Ceta_%7Bmn%7Ddx%5Em+dx%5En+%2B+B%28r%29dr%5E2+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = A(r)\eta_{mn}dx^m dx^n + B(r)dr^2 .' title='ds^2 = A(r)\eta_{mn}dx^m dx^n + B(r)dr^2 .' class='latex' /></p>
<p>We have coordinates <img src='http://l.wordpress.com/latex.php?latex=C%5EM+%3D+%5Cleft%28x_0+%2C+x_1+%2Cx_2+%2C+x_3+%2Cr%5Cright%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^M = \left(x_0 , x_1 ,x_2 , x_3 ,r\right)' title='C^M = \left(x_0 , x_1 ,x_2 , x_3 ,r\right)' class='latex' /> and we will work in a static gauge where a worldsheet will be parametrized by the two spacetime coordinates <img src='http://l.wordpress.com/latex.php?latex=x_1%2C+x_2&#038;bg=fff&#038;fg=222&#038;s=0' alt='x_1, x_2' title='x_1, x_2' class='latex' />. We will set <img src='http://l.wordpress.com/latex.php?latex=x_3+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='x_3 = 0' title='x_3 = 0' class='latex' />.</p>
<p>Then taking derivatives of the coordinate vector we have:</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7B1%7D+C%5EM+%3D+%5Cleft%28%5Cpartial_%7B1%7Dx_0%2C+1%2C+0%2C+0%2C+%5Cpartial_%7B1%7Dr%5Cright%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{1} C^M = \left(\partial_{1}x_0, 1, 0, 0, \partial_{1}r\right)' title='\partial_{1} C^M = \left(\partial_{1}x_0, 1, 0, 0, \partial_{1}r\right)' class='latex' />&nbsp;&nbsp; and&nbsp;&nbsp; <img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7B2%7D+C%5EM+%3D+%5Cleft%28%5Cpartial_%7B2%7Dx_0%2C+0%2C+1%2C+0%2C+%5Cpartial_%7B2%7Dr%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{2} C^M = \left(\partial_{2}x_0, 0, 1, 0, \partial_{2}r\right).' title='\partial_{2} C^M = \left(\partial_{2}x_0, 0, 1, 0, \partial_{2}r\right).' class='latex' /></p>
<p>Then, the ingredients that go into the Nambu-Goto lagrangian are:</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=%5Cleft%28%5Cpartial_%7B1%7DC%5Cright%29%5E2+%3D+-A%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E2+-+1%5Cright%5D%2BB%5Cleft%28%5Cpartial_%7B1%7Dr%5Cright%29%5E2+&#038;bg=fff&#038;fg=222&#038;s=0' alt='\left(\partial_{1}C\right)^2 = -A\left[\left(\partial_{1}x_{0}\right)^2 - 1\right]+B\left(\partial_{1}r\right)^2 ' title='\left(\partial_{1}C\right)^2 = -A\left[\left(\partial_{1}x_{0}\right)^2 - 1\right]+B\left(\partial_{1}r\right)^2 ' class='latex' />&nbsp;&nbsp; and&nbsp;&nbsp; <img src='http://l.wordpress.com/latex.php?latex=%5Cleft%28%5Cpartial_%7B2%7DC%5Cright%29%5E2+%3D+-A%5Cleft%5B%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E2+-+1%5Cright%5D%2BB%5Cleft%28%5Cpartial_%7B2%7Dr%5Cright%29%5E2+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\left(\partial_{2}C\right)^2 = -A\left[\left(\partial_{2}x_{0}\right)^2 - 1\right]+B\left(\partial_{2}r\right)^2 .' title='\left(\partial_{2}C\right)^2 = -A\left[\left(\partial_{2}x_{0}\right)^2 - 1\right]+B\left(\partial_{2}r\right)^2 .' class='latex' /></p>
<p>The cross term goes as:</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=%5Cpartial_%7B1%7DC+%5Ccdot+%5Cpartial_%7B2%7DC+%3D+-A%5Cpartial_%7B1%7Dx_0+%5Cpartial_%7B2%7Dx_0+%2B+B%5Cpartial_%7B1%7Dr%5Cpartial_%7B2%7Dr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\partial_{1}C \cdot \partial_{2}C = -A\partial_{1}x_0 \partial_{2}x_0 + B\partial_{1}r\partial_{2}r.' title='\partial_{1}C \cdot \partial_{2}C = -A\partial_{1}x_0 \partial_{2}x_0 + B\partial_{1}r\partial_{2}r.' class='latex' /></p>
<p>The determinant of the induced metric will be denoted by:</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=-G+%3D+%5Cleft%28%5Cpartial_%7B1%7DC+%5Ccdot+%5Cpartial_%7B2%7DC%5Cright%29%5E2+-+%5Cleft%28%5Cpartial_%7B1%7DC%5Cright%29%5E2+%5Cleft%28%5Cpartial_%7B2%7DC%5Cright%29%5E2+.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-G = \left(\partial_{1}C \cdot \partial_{2}C\right)^2 - \left(\partial_{1}C\right)^2 \left(\partial_{2}C\right)^2 .' title='-G = \left(\partial_{1}C \cdot \partial_{2}C\right)^2 - \left(\partial_{1}C\right)^2 \left(\partial_{2}C\right)^2 .' class='latex' /></p>
<p>We see that since we have:</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=%5Cleft%28%5Cpartial_%7B1%7DC+%5Ccdot+%5Cpartial_%7B2%7DC%5Cright%29%5E2+%3D+A%5E2+%28%5Cpartial_1+x_0%29%5E2+%28%5Cpartial_2+x_0%29%5E2+%2B+B%5E2+%28%5Cpartial_1+r%29%5E2+%28%5Cpartial_2+r%29%5E2+-+2AB+%5Cpartial_1+x_0+%5Cpartial_2+x_0+%5Cpartial_1+r+%5Cpartial_2+r+%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\left(\partial_{1}C \cdot \partial_{2}C\right)^2 = A^2 (\partial_1 x_0)^2 (\partial_2 x_0)^2 + B^2 (\partial_1 r)^2 (\partial_2 r)^2 - 2AB \partial_1 x_0 \partial_2 x_0 \partial_1 r \partial_2 r ,' title='\left(\partial_{1}C \cdot \partial_{2}C\right)^2 = A^2 (\partial_1 x_0)^2 (\partial_2 x_0)^2 + B^2 (\partial_1 r)^2 (\partial_2 r)^2 - 2AB \partial_1 x_0 \partial_2 x_0 \partial_1 r \partial_2 r ,' class='latex' /></p>
<p>and</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cleft%28%5Cpartial_%7B1%7DC%5Cright%29%5E%7B2%7D+%5Cleft%28%5Cpartial_%7B2%7DC%5Cright%29%5E%7B2%7D+%3D+A%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E2+-+1%5Cright%5D+%5Cleft%5B%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E2+-+1%5Cright%5D+%2B+B%5E%7B2%7D+%28%5Cpartial_1+r%29%5E2+%28%5Cpartial_2+r%29%5E2+-+AB%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dr%5Cright%29%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D-1%5Cright%5D%2B%5Cleft%28%5Cpartial_%7B2%7Dr%5Cright%29%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D-1%5Cright%5D%5Cright%5D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\left(\partial_{1}C\right)^{2} \left(\partial_{2}C\right)^{2} = A^{2}\left[\left(\partial_{1}x_{0}\right)^2 - 1\right] \left[\left(\partial_{2}x_{0}\right)^2 - 1\right] + B^{2} (\partial_1 r)^2 (\partial_2 r)^2 - AB\left[\left(\partial_{1}r\right)^{2}\left[\left(\partial_{2}x_{0}\right)^{2}-1\right]+\left(\partial_{2}r\right)^{2}\left[\left(\partial_{1}x_{0}\right)^{2}-1\right]\right].' title='\left(\partial_{1}C\right)^{2} \left(\partial_{2}C\right)^{2} = A^{2}\left[\left(\partial_{1}x_{0}\right)^2 - 1\right] \left[\left(\partial_{2}x_{0}\right)^2 - 1\right] + B^{2} (\partial_1 r)^2 (\partial_2 r)^2 - AB\left[\left(\partial_{1}r\right)^{2}\left[\left(\partial_{2}x_{0}\right)^{2}-1\right]+\left(\partial_{2}r\right)^{2}\left[\left(\partial_{1}x_{0}\right)^{2}-1\right]\right].' class='latex' /></p>
<p>we get some cancellations in <img src='http://l.wordpress.com/latex.php?latex=-G&#038;bg=fff&#038;fg=222&#038;s=0' alt='-G' title='-G' class='latex' />. In the end we can write</p>
<p align="center"><img src='http://l.wordpress.com/latex.php?latex=-G+%3D+-A%5E%7B2%7D+-+2AB%5Cpartial_%7B1%7Dx_%7B0%7D+%5Cpartial_%7B2%7Dx_%7B0%7D+%5Cpartial_%7B1%7Dr+%5Cpartial_%7B2%7Dr+%2B+A%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D+%2B+%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D+%5Cright%5D+%2B+AB%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dr%5Cright%29%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D-1%5Cright%5D%2B%5Cleft%28%5Cpartial_%7B2%7Dr%5Cright%29%5E%7B2%7D%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D-1%5Cright%5D%5Cright%5D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='-G = -A^{2} - 2AB\partial_{1}x_{0} \partial_{2}x_{0} \partial_{1}r \partial_{2}r + A^{2}\left[\left(\partial_{1}x_{0}\right)^{2} + \left(\partial_{2}x_{0}\right)^{2} \right] + AB\left[\left(\partial_{1}r\right)^{2}\left[\left(\partial_{2}x_{0}\right)^{2}-1\right]+\left(\partial_{2}r\right)^{2}\left[\left(\partial_{1}x_{0}\right)^{2}-1\right]\right].' title='-G = -A^{2} - 2AB\partial_{1}x_{0} \partial_{2}x_{0} \partial_{1}r \partial_{2}r + A^{2}\left[\left(\partial_{1}x_{0}\right)^{2} + \left(\partial_{2}x_{0}\right)^{2} \right] + AB\left[\left(\partial_{1}r\right)^{2}\left[\left(\partial_{2}x_{0}\right)^{2}-1\right]+\left(\partial_{2}r\right)^{2}\left[\left(\partial_{1}x_{0}\right)^{2}-1\right]\right].' class='latex' /></p>
<p>We can write the lagrangian as:</p>
<p><img src='http://l.wordpress.com/latex.php?latex=L_%7BNG%7D+%3D+%5Csqrt%7BAJ%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='L_{NG} = \sqrt{AJ},' title='L_{NG} = \sqrt{AJ},' class='latex' /></p>
<p>with</p>
<p><img src='http://l.wordpress.com/latex.php?latex=J+%3D+A%5Cleft%5B%5Cleft%28%5Cpartial_%7B1%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D+%2B+%5Cleft%28%5Cpartial_%7B2%7Dx_%7B0%7D%5Cright%29%5E%7B2%7D+-+1+%5Cright%5D+%2B+B+%5Cleft%5B%5Cright%5D%5E%7B2%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='J = A\left[\left(\partial_{1}x_{0}\right)^{2} + \left(\partial_{2}x_{0}\right)^{2} - 1 \right] + B \left[\right]^{2}' title='J = A\left[\left(\partial_{1}x_{0}\right)^{2} + \left(\partial_{2}x_{0}\right)^{2} - 1 \right] + B \left[\right]^{2}' class='latex' /></p>
<img alt="" border="0" src="http://feeds.wordpress.com/1.0/categories/indexguy.wordpress.com/126/" /> <img alt="" border="0" src="http://feeds.wordpress.com/1.0/tags/indexguy.wordpress.com/126/" /> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/indexguy.wordpress.com/126/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/indexguy.wordpress.com/126/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/indexguy.wordpress.com/126/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/indexguy.wordpress.com/126/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/indexguy.wordpress.com/126/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/indexguy.wordpress.com/126/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/indexguy.wordpress.com/126/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/indexguy.wordpress.com/126/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/indexguy.wordpress.com/126/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/indexguy.wordpress.com/126/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=126&subd=indexguy&ref=&feed=1" /></div>]]></content:encoded>
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		<title>Back to zero</title>
		<link>http://indexguy.wordpress.com/2008/07/21/back-to-zero/</link>
		<comments>http://indexguy.wordpress.com/2008/07/21/back-to-zero/#comments</comments>
		<pubDate>Mon, 21 Jul 2008 19:28:05 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Organizational]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=122</guid>
		<description><![CDATA[It turns out that all that I have been doing for the past few weeks has been slightly off-track. Back to the main source: Alday and Maldacena.
       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=122&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>It turns out that all that I have been doing for the past few weeks has been slightly off-track. Back to the main source: Alday and Maldacena.</p>
<img alt="" border="0" src="http://feeds.wordpress.com/1.0/categories/indexguy.wordpress.com/122/" /> <img alt="" border="0" src="http://feeds.wordpress.com/1.0/tags/indexguy.wordpress.com/122/" /> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/indexguy.wordpress.com/122/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/indexguy.wordpress.com/122/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/indexguy.wordpress.com/122/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/indexguy.wordpress.com/122/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/indexguy.wordpress.com/122/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/indexguy.wordpress.com/122/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/indexguy.wordpress.com/122/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/indexguy.wordpress.com/122/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/indexguy.wordpress.com/122/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/indexguy.wordpress.com/122/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=122&subd=indexguy&ref=&feed=1" /></div>]]></content:encoded>
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		<title>Alday &amp; Roiban give us 100 pages of goodness</title>
		<link>http://indexguy.wordpress.com/2008/07/14/alday-roiban-give-us-100-pages-of-goodness/</link>
		<comments>http://indexguy.wordpress.com/2008/07/14/alday-roiban-give-us-100-pages-of-goodness/#comments</comments>
		<pubDate>Mon, 14 Jul 2008 23:49:40 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Sparkling on the arXiv]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=120</guid>
		<description><![CDATA[Today I found this:
Luis Fernando Alday and Radu Roiban, Scattering amplitudes, Wilson loops and the Strings/Gauge Theory correspondence, arXiv:0807.1889.
At this moment it looks really helpful.
       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=120&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Today I found this:</p>
<blockquote><p>Luis Fernando Alday and Radu Roiban, <strong><em>Scattering amplitudes, Wilson loops and the Strings/Gauge Theory correspondence</em></strong>, <a href="http://arxiv.org/abs/0807.1889">arXiv:0807.1889</a>.</p></blockquote>
<p>At this moment it looks really helpful.</p>
<img alt="" border="0" src="http://feeds.wordpress.com/1.0/categories/indexguy.wordpress.com/120/" /> <img alt="" border="0" src="http://feeds.wordpress.com/1.0/tags/indexguy.wordpress.com/120/" /> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gocomments/indexguy.wordpress.com/120/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/comments/indexguy.wordpress.com/120/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godelicious/indexguy.wordpress.com/120/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/delicious/indexguy.wordpress.com/120/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/gostumble/indexguy.wordpress.com/120/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/stumble/indexguy.wordpress.com/120/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/godigg/indexguy.wordpress.com/120/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/digg/indexguy.wordpress.com/120/" /></a> <a rel="nofollow" href="http://feeds.wordpress.com/1.0/goreddit/indexguy.wordpress.com/120/"><img alt="" border="0" src="http://feeds.wordpress.com/1.0/reddit/indexguy.wordpress.com/120/" /></a> <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=120&subd=indexguy&ref=&feed=1" /></div>]]></content:encoded>
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		<title>Updated roadmap</title>
		<link>http://indexguy.wordpress.com/2008/07/13/updated-roadmap/</link>
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		<pubDate>Sun, 13 Jul 2008 23:13:43 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[AdS/CFT]]></category>
		<category><![CDATA[Relativity]]></category>
		<category><![CDATA[String Theory]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=119</guid>
		<description><![CDATA[I have become more comfortable with the &#8220;T-dual&#8221; transformation and now I am confident on what to consider.
Exact adS can be described by the metric

After the T-transformation the metric returns to the same form but now ,

Both of these spaces can be described by embedding a hyper-surface in . They both have scale invariance.
There are [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=119&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>I have become more comfortable with the &#8220;T-dual&#8221; transformation and now I am confident on what to consider.</p>
<p>Exact adS can be described by the metric</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Cleft%28%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+dr%5E2%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right).' title='ds^2 = \displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right).' class='latex' /></p>
<p>After the T-transformation the metric returns to the same form but now <img src='http://l.wordpress.com/latex.php?latex=r+%3D+R%5E2+%2F+%5Crho&#038;bg=fff&#038;fg=222&#038;s=0' alt='r = R^2 / \rho' title='r = R^2 / \rho' class='latex' />,</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7B%5Crho%5E2%7D+%5Cleft%28%5Ceta_%7Bmn%7Ddx%5Em+dx%5En+%2B+d%5Crho%5E2%5Cright%29.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{\rho^2} \left(\eta_{mn}dx^m dx^n + d\rho^2\right).' title='ds^2 = \displaystyle\frac{R^2}{\rho^2} \left(\eta_{mn}dx^m dx^n + d\rho^2\right).' class='latex' /></p>
<p>Both of these spaces can be described by embedding a hyper-surface in <img src='http://l.wordpress.com/latex.php?latex=R_%7B2%2Cd%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='R_{2,d}' title='R_{2,d}' class='latex' />. They both have scale invariance.</p>
<p>There are two extra-dimensional spaces that one can obtain by embedding a hyper-surface in <img src='http://l.wordpress.com/latex.php?latex=R_%7B3%2Cd%7D&#038;bg=fff&#038;fg=222&#038;s=0' alt='R_{3,d}' title='R_{3,d}' class='latex' /> and reduce to adS in some limit.</p>
<p><em><strong>Case I:</strong></em> <img src='http://l.wordpress.com/latex.php?latex=C%5E2+%3D+0&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^2 = 0' title='C^2 = 0' class='latex' /></p>
<p>For this case anti-de Sitter space is obtained by setting the extra coordinate equal to <img src='http://l.wordpress.com/latex.php?latex=R&#038;bg=fff&#038;fg=222&#038;s=0' alt='R' title='R' class='latex' />. The metric in the original Poincaré coordinates looks like:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+%5Cdisplaystyle%5Cfrac%7Bz%5E2%7D%7Br%5E2%7Ddr%5E2+%2B+dz%5E2+%2B+2%5Cfrac%7Bz%7D%7Br%7Ddzdr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 + 2\frac{z}{r}dzdr.' title='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 + 2\frac{z}{r}dzdr.' class='latex' /></p>
<p>After the T-transformation (leaving the <img src='http://l.wordpress.com/latex.php?latex=z&#038;bg=fff&#038;fg=222&#038;s=0' alt='z' title='z' class='latex' /> coordinate intact) one obtains</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7B%5Crho%5E2%7D+%5Ceta_%7Bmn%7Ddx%5Em+dx%5En+%2B+%5Cdisplaystyle%5Cfrac%7Bz%5E2%7D%7B%5Crho%5E2%7Dd%5Crho%5E2+%2B+dz%5E2+-+2%5Cfrac%7Bz%7D%7B%5Crho%7Ddz+d%5Crho.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{\rho^2} \eta_{mn}dx^m dx^n + \displaystyle\frac{z^2}{\rho^2}d\rho^2 + dz^2 - 2\frac{z}{\rho}dz d\rho.' title='ds^2 = \displaystyle\frac{R^2}{\rho^2} \eta_{mn}dx^m dx^n + \displaystyle\frac{z^2}{\rho^2}d\rho^2 + dz^2 - 2\frac{z}{\rho}dz d\rho.' class='latex' /></p>
<p><em><strong>Case II:</strong></em> <img src='http://l.wordpress.com/latex.php?latex=C%5E2+%3D+-R%5E2&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^2 = -R^2' title='C^2 = -R^2' class='latex' /></p>
<p>Now adS is reached when the extra coordinate vanishes. In Poincaré coordinates,</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Cleft%28%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+dr%5E2%5Cright%29+%2B+%5Cdisplaystyle%5Cfrac%7Bz%5E2%7D%7Br%5E2%7Ddr%5E2+%2B+dz%5E2+%2B+2%5Cfrac%7Bz%7D%7Br%7Ddzdr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right) + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 + 2\frac{z}{r}dzdr.' title='\displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right) + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 + 2\frac{z}{r}dzdr.' class='latex' /></p>
<p>While in the T-coordinates we obtain</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Cleft%28%5Ceta_%7Bmn%7Ddx%5Em+dx%5En+%2B+dr%5E2%5Cright%29+%2B+%5Cdisplaystyle%5Cfrac%7Bz%5E2%7D%7Br%5E2%7Ddr%5E2+%2B+dz%5E2+-+2%5Cfrac%7Bz%7D%7Br%7Ddzdr.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dx^m dx^n + dr^2\right) + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 - 2\frac{z}{r}dzdr.' title='\displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dx^m dx^n + dr^2\right) + \displaystyle\frac{z^2}{r^2}dr^2 + dz^2 - 2\frac{z}{r}dzdr.' class='latex' /></p>
<p>Note that both of these cases have scale-invariance in the coordinates <img src='http://l.wordpress.com/latex.php?latex=%28r%2C+y%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(r, y)' title='(r, y)' class='latex' /> and <img src='http://l.wordpress.com/latex.php?latex=%28%5Crho%2C+x%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(\rho, x)' title='(\rho, x)' class='latex' />. These two cases are atractive because they can be constructed straight from a higher-dimensional reduction. On the other hand one can just modify the adS metric and see what happens. Here are some of the modifications.</p>
<ul>
<li>Soft wall: <img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D%5Cleft%28+1+%2B+A%5E2%28r%29%5Cright%29dr%5E2&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{R^2}{r^2}\left( 1 + A^2(r)\right)dr^2' title='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{R^2}{r^2}\left( 1 + A^2(r)\right)dr^2' class='latex' /></li>
<li>Hard wall: <img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Cleft%28%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+dr%5E2%5Cright%29%5Ctheta%28r+-+r_%7B0%7D%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right)\theta(r - r_{0})' title='ds^2 = \displaystyle\frac{R^2}{r^2} \left(\eta_{mn}dy^m dy^n + dr^2\right)\theta(r - r_{0})' class='latex' /></li>
<li>Cutoff: <img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7D+%5Ceta_%7Bmn%7Ddy%5Em+dy%5En+%2B+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2+-+a%5E2%7Ddr%5E2&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{R^2}{r^2 - a^2}dr^2' title='ds^2 = \displaystyle\frac{R^2}{r^2} \eta_{mn}dy^m dy^n + \displaystyle\frac{R^2}{r^2 - a^2}dr^2' class='latex' /></li>
</ul>
<p>I might not want to keep the scale invariance so obvious for the <img src='http://l.wordpress.com/latex.php?latex=y&#038;bg=fff&#038;fg=222&#038;s=0' alt='y' title='y' class='latex' /> coordinates.</p>
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		<title>Yet another candidate</title>
		<link>http://indexguy.wordpress.com/2008/07/09/yet-another-candidate/</link>
		<comments>http://indexguy.wordpress.com/2008/07/09/yet-another-candidate/#comments</comments>
		<pubDate>Wed, 09 Jul 2008 22:49:18 +0000</pubDate>
		<dc:creator>Index Guy</dc:creator>
				<category><![CDATA[Relativity]]></category>

		<guid isPermaLink="false">http://indexguy.wordpress.com/?p=116</guid>
		<description><![CDATA[Today I found yet another space that looks promising. This one looks even more nicer than the previous cases. To obtain the metric one can start with the product of 3-d Minkowski and d-dimensional Minkowski space. The coordinates can be taken as

with  a two-dimensional Minkowski index and  a d-dimensional Minkowski index. Let us [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=indexguy.wordpress.com&blog=1356843&post=116&subd=indexguy&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Today I found yet another space that looks promising. This one looks even more nicer than the previous cases. To obtain the metric one can start with the product of 3-d Minkowski and d-dimensional Minkowski space. The coordinates can be taken as</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=C%5E%7BM%7D+%3D+%28Z%5EA%2C+z%2C+Y%5Em%29%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^{M} = (Z^A, z, Y^m),' title='C^{M} = (Z^A, z, Y^m),' class='latex' /></p>
<p>with <img src='http://l.wordpress.com/latex.php?latex=A&#038;bg=fff&#038;fg=222&#038;s=0' alt='A' title='A' class='latex' /> a two-dimensional Minkowski index and <img src='http://l.wordpress.com/latex.php?latex=m&#038;bg=fff&#038;fg=222&#038;s=0' alt='m' title='m' class='latex' /> a d-dimensional Minkowski index. Let us write the metric as:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+-2dZ_%7B%2B%7DdZ_%7B-%7D+%2B+dz+%2B+%5Ceta_%7Bmn%7DdY%5E%7Bm%7DdY%5E%7Bn%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = -2dZ_{+}dZ_{-} + dz + \eta_{mn}dY^{m}dY^{n}.' title='ds^2 = -2dZ_{+}dZ_{-} + dz + \eta_{mn}dY^{m}dY^{n}.' class='latex' /></p>
<p>Now one imposes the condition:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=C%5E2+%3D+0%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='C^2 = 0,' title='C^2 = 0,' class='latex' /></p>
<p>and introduces &#8220;Poincaré coordinates&#8221; that satisfy this constrain. These can be defined as:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=Y%5Em+%3D+%5Cdisplaystyle%5Cfrac%7BR%7D%7Br%7Dy%5Em%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='Y^m = \displaystyle\frac{R}{r}y^m,' title='Y^m = \displaystyle\frac{R}{r}y^m,' class='latex' />      <img src='http://l.wordpress.com/latex.php?latex=%5Csqrt%7B2%7DZ_%7B%2B%7D+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%7D%2C&#038;bg=fff&#038;fg=222&#038;s=0' alt='\sqrt{2}Z_{+} = \displaystyle\frac{R^2}{r},' title='\sqrt{2}Z_{+} = \displaystyle\frac{R^2}{r},' class='latex' />      <img src='http://l.wordpress.com/latex.php?latex=%5Csqrt%7B2%7DZ_%7B-%7D+%3D+%5Cdisplaystyle+%5Cfrac%7Br+z%5E2%7D%7BR%5E2%7D+%2B+%5Cdisplaystyle%5Cfrac%7B%5Ceta_%7Bmn%7Dy%5Em+y%5En%7D%7Br%7D.&#038;bg=fff&#038;fg=222&#038;s=0' alt='\sqrt{2}Z_{-} = \displaystyle \frac{r z^2}{R^2} + \displaystyle\frac{\eta_{mn}y^m y^n}{r}.' title='\sqrt{2}Z_{-} = \displaystyle \frac{r z^2}{R^2} + \displaystyle\frac{\eta_{mn}y^m y^n}{r}.' class='latex' /></p>
<p>Then writing the metric in terms of these coordinates one obtains:</p>
<p style="text-align:center;"><img src='http://l.wordpress.com/latex.php?latex=ds%5E2+%3D+%5Cdisplaystyle%5Cfrac%7BR%5E2%7D%7Br%5E2%7Ddy%5E2+%2B+%5Cfrac%7Bz%5E2%7D%7Br%5E2%7Ddr%5E2+%2B+%5Cfrac%7B2z%7D%7Br%7Ddrdz+%2B+dz%5E2.&#038;bg=fff&#038;fg=222&#038;s=0' alt='ds^2 = \displaystyle\frac{R^2}{r^2}dy^2 + \frac{z^2}{r^2}dr^2 + \frac{2z}{r}drdz + dz^2.' title='ds^2 = \displaystyle\frac{R^2}{r^2}dy^2 + \frac{z^2}{r^2}dr^2 + \frac{2z}{r}drdz + dz^2.' class='latex' /></p>
<p>One can see that when we set <img src='http://l.wordpress.com/latex.php?latex=z+%3D+R&#038;bg=fff&#038;fg=222&#038;s=0' alt='z = R' title='z = R' class='latex' /> we obtain exact d-dimensional anti-de Sitter space. This metric is very atractive. It contains more symmetry than the other cases that I have consider previously. Besides the first term being invariant under Poincaré transformations, one also has an invariance under the rescalling of the <img src='http://l.wordpress.com/latex.php?latex=%28y%5Em+%2C+r%29&#038;bg=fff&#038;fg=222&#038;s=0' alt='(y^m , r)' title='(y^m , r)' class='latex' /> coordinates. I shall explore this space further.</p>
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